Assuming that the distribution Essay Example for Free

Assuming that the dissemination Essay1. Assuming that the scattering is recipe for weight intercourse to the ideal and 99% of the male participants scored between (53.68, 64.64), where did 95% of the values for weight relative to the ideal lie? one shot your cause to two ten-fold places. x=5.48, SD=22.935.48+1.96(22.93) = 170.59925.48-1.96(22.93)=80.7136(80.71,170.60)2. Which of the following values from tabular array 1 tells us about variability of the gobs in a distribution? c. 22.573. Assuming that the distribution for General wellness Perceptions is normal, 95% of the females slews some the take to be were between what values? Round your answer to two decimal places. x=39.71, SD=25.4639.71+1.96(25.46) = 89.611639.71-1.96(25.46) = -10.1916(-10.19, 89.61)4. Assuming that the distribution of scores for Pain is normal, 95% of the mens scores around the mean were between what two values? Round your answer to two decimal places. x=52.53, SD=30.9052.53+1.96(30.90) = 113 .09452.53-1.96(30.90) = -8.034(-8.03, 113.09)5. Were the body image scores significantly different for women versus men? Provide a rule for your answer. Yes, body image scores were significantly higher for women (73.1 17.0) than men (60.2 17.0).6. Assuming that the distribution of Mental Health scores for men is normal, where are 99% of the mens mental health scores around the mean in this distribution? Round your answer to two decimal places. x= 57.09, SD=23.7257.09+2.58(23.72)= 118.287657.09-2.58(23.72)= -4.1076(-4.11, 118.29)7. Assuming that the distribution of scores for Physical Functioning in women is normal, where are 99% of the womens scores around the mean in this distribution? Round your answer to two decimal places. X= 65.20, SD=29.79 65.20+2.58(29.79) = 142.058265.20-2.58(29.79) = -11.6582(-11.66, 142.06)8. Assuming that the distribution of scores is normal, 99% of HIV-positive body image scores around the mean were between what two values? Round your answer to two d ecimal places. Body image scores for Male x= 60.22, SD=16.98 Female x= 73.07, SD= 16.93 Male 60.22+2.58(16.98)= 104.028460.22-2.58(16.98)= 16.4116Female 73.07+2.58(16.93)= 116.749473.07-2.58(16.93)= 29.3906Male and Female HIV+ Body Image scores combined are between (16.41, 116.75)9. Assuming that the distribution of scores for Role Functioning is normal, 99% of the mens scores around the mean were between what values? Round your answer to two decimal places. x=50.00, SD=46.2950.00+2.58(46.29)= 169.428250.00-2.58(46.29)=-69.4282(-69.43,169.43)